4x^2-3x2-8x-8=0

Solution for 4x^2-3x2-8x-8=0 equation:

4x^2-3x^2-8x-8=0

We add all the numbers together, and all the variables

x^2-8x-8=0

a = 1; b = -8; c = -8;
Δ = b2-4ac
Δ = -82-4·1·(-8)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{6}}{2*1}=\frac{8-4\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{6}}{2*1}=\frac{8+4\sqrt{6}}{2}
$